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If sin (theta) = 2/3, cos² (theta) = 1 (2/3)² = 1–4/9 = 5/9 => cos (theta) = V5/3 or cos (theta) = V5/3 ( you can't know the sign with theMore analytically, squaring both sides yields sin^2(theta) 2sin(theta)cos(theta) cos^2(theta) = 1 sin(2*theta) = 2 Now we have 1 sin(2*theta) = 2, so sin(2*theta) = 1, and thus 2*theta = pi/2 kpi, for any integer k Dividing by 2, theta = pi/4 k*pi/2

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Cos theta =-√3/2 find theta- The Questions and Answers of If √3 tan theta =3 sin theta , then find the value of sin^2 theta cos^2 theta?  If cos theta is 1/root 2 then you see in tratio table cos attains value 1/root 2 at 45° which means value of theta is 45° then find the value of cot 45° which is 1 then 41 =5 2 Comments Dislike Bookmark Mohammad Shabbir Alam From the given condition, CosΘ = 1/√2 CosΘ = Cos45º ∴ Θ = 45º Now

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Find sin 2 theta 2 See answers Advertisement Advertisement shawais786 shawais786 Answer Answer is option "a" ie Stepbystep explanation length of perpendicular = √7 Now, to find sinФ and cosФThe formula of cos of three times of theta is given by Cos 3θ = 4cos 3 θ The measures of the sides are x, x√3, and 2x In a 30°−60°−90° triangle, the length of the hypotenuse is twice the length of the shorter leg, and the length of the longer leg is √3 times the length of the Select all that apply (there are 3 answers) A cos^2(theta)=sin^2(theta)1 B sin(theta)=1/csc(theta) C sec(theta)=1/cot(theta) D cot(theta)=cos/sin(theta) E Math) 1 Simplify the expression csc^2(x1)/1sin x a csc x1 b csc x(csc x1) c sin^2 xcsc x**** d csc^2 xcos xtan x 2

Are solved by group of students and teacher of Class 10, which is also the largest student community of Class 10We have to find the area enclosed by one loop of the following polar curve {eq}\displaystyle r = \cos 2 \theta {/eq} So, here we know that the graph of this polar curve is, as followsIf √3 tanθ = 3 sinθ, then the value of (sin 2 θ – cos 2 θ) is If √3 tanθ = 3 sinθ, then the value of (sin 2 θ – cos 2 θ) is 1 3 1/3

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Answered 9 months ago Author has 803 answers and 1537K answer views sin² (x) cos² (x) = 1 for any x!!Solution for If cos theta = 1/3 and theta is in Quadrant III, find (tan theta)*(cot theta) (csc theta)

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